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Name: _________________________________ #: ____ Class: ____ Date: ________________Concentrations of Solutions PracticeCalculate the concentration in each of the following solutions:10 moles of potassium hydroxide in 5.16 L of solution0.5 moles of calcium chloride in 485 mL of solution0.079 moles of magnesium sulfate in 25 mL of solutionFind the number of moles of solute in each of the following solutions:2L of 2.3 M nitric acid200 mL of 0.8 M sodium carbonate solution300 mL of 4 M sodium hydroxide solutionHow many grams of NaOH must be used to make 250 mL of a 1.842 M solution of NaOH?a. Start with what you know, the final volume and concentration of the solution. Arrange these factors to calculate the moles of NaOH needed.b. Change moles of NaOH to grams of NaOH.Calculate the concentration of a solution of CO2 in water, which contains 20.25 g of CO2 per 675 mL of solution.a. Start with what you know, change grams of CO2 to moles of CO2. b. With the moles value found in part a, use the concentration formula to calculate the concentration of CO2.The initial concentration of the solution H2SO4 is 18 M. What would the volume of the initial stock solution (V1) need to be if the concentration was being changed to 0.4 M of a 1 L solution?The initial concentration of the solution HCl is 12 M. What would the volume of the initial stock solution (V1) need to be if the concentration was being changed to 1.1 M of a 500-mL solution?The initial concentration of the solution HNO3 is 16 M. What would the volume of the initial stock solution (V1) need to be if the concentration was being changed to 5.5 M of a 325-mL solution?

What is general solution in trigonometry? Trigonometric Equations Principal Solutions of Trigonometric Equations. Find the principal solutions of the equation = . Now, we know that = . ... General Solutions of Trigonometric Equations. Theorem 1: For any real numbers x and y, = implies x = nπ + (-1) n y, where n ∈ Z. ... More Solved Problems on Trigonometric Equations. Find the principal and general solutions of = 2. ...