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Velocity, distance and time - velocity distance equation


Velocity, distance and time-velocity distance equation

Velocity, distance and time
Problem 1:Generally, we know the equation for velocity (a rate) to be:
Where v = velocity, d = distance and t = time.
This equation can be rearranged so that you have an
equation for distance (d) and time (t).
1. Rearrange the velocity equation to create an equation for distance (d).
2. Rearrange the velocity equation to create an equation for time (t).
Use the equations that you manipulated above to solve the following problems:
Problem 2: A wave traveling downward
from the surface of the ocean at 1.5 km/sec
takes six seconds to reflect off the ocean
floor. How deep is the ocean at that site?
Problem 3: Imagine that you are working
with Ms. Homeowner to understand the
groundwater flow in her area. She is
particularly interested in an underground tank that is located 2.6 km from her home. You have
measured the velocity of the groundwater to be 0.033 km/day. About how long will it take any
contaminants leaking from the tank to reach Ms. Homeowner's well?
Density
Density plays an important role in our understanding of the physical properties of Earth
materials. The equation for density is similar to that for velocity and, as such, it can be
manipulated so that you can solve for any of the variables involved. The next few problems
utilize the equation for density:
which can be shortened to:
Problem 1: Manipulate (rearrange) the density equation (above) to create an equation for mass.
Problem 2:Manipulate the density equation to create an equation for volume.
Use the equations that you manipulated above to solve the following problems:
Problem 3:Continental crust has a density of about 2.75 g/cm3. What volume would 1000 g (1
kg) of continental crust occupy?
Problem 4:The outer core has a density of about 10.5 g/cm3. What volume would 1000 g (1 kg)
of the outer core occupy?
Isostasy
Isostasy is an important concept in the geosciences
that is related to density. The concept of isostasy
explains why continental crust sits so much higher
than oceanic crust. It involves properties of an
object like height and density. It also explains why
only a portion of an iceberg is visible above water.
The following problems involve an equation that is
important to understanding the way that continental
crust/oceanic crust behave on the Earth. If you need
help visualizing the problem, click on the
illustration below to see a larger version.
The equation for calculating the height of an object above the "fluid" in which it is floating is:
where:
Htotal = total height of the object
object = density of the object of interest (e.g., iceberg, continental crust, etc.)
fluid = density of the fluid in which the object is floating (e.g., seawater, mantle, etc.)
Habove = height of the object visible above the fluid.
Problem 1: Rearrange the equation above to solve for Htotal.
Problem 2: Use the equation that you generated in Problem 1 to calculate the thickness
(Htotal) of continental crust if:
? the density of continental crust (object) is 2.79 g/cm3,
? the density of the mantle (fluid) is 3.3 g/cm3,
? and, the average height of the continents above the mantle is 4.5 km (Habove).
Problem 3: Use the information from Problem 2 to calculate the thickness of crust that lies
below the mantle (e.g., Hbelow).

What is the equation used to calculate distance? To calculate the 2-D distance between these two points, follow these steps: Input the values into the formula: √ [ (x₂ - x₁)² + (y₂ - y₁)²]. Subtract the values in the parentheses. Square both quantities in the parentheses. Add the results. Take the square root. Use the distance calculator to check your results.