b. L0, R0 are derived by passing the 64-plaintext through IP (Table 3.2a): L0 = 1100 1100 0000 0000 1100 1100 1111 1111 R0 = 1111 0000 1010 1010 1111 0000 1010 1010 c.
https://www.ee.nthu.edu.tw/whhsu/ComSecu96/Solutions-Crypto4e.doc
If the numbers are large enough, and M1 and M2 are sufficiently random to make it impractical to work backwards, p cannot be found without knowing k. 9.2 a. n = 33; (n) = 20; d = 3; C = 26.
https://www.ee.nthu.edu.tw/whhsu/ComSecu96/Solutions-Crypto4e.doc
Ans: Suppose n 1 is even. Therefore n 1 2k. Therefore n 2k 1 2(k 1) 1, which is odd.
http://faculty.ccp.edu/FACULTY/akitover/163/Lena/Chapter1.doc
doc for "which expression is equivalent to assume k0".(Page 1 of about 14 results)