You can write the Keq expression for a chemical reaction by putting products over reactants, coefficients become exponents, and liquids and solids get ignore...
A system which is not at equilibrium will move spontaneously to a position of being at equilibrium. The same argument that was used for solids can also be used for liquids. Thus, we can expand the last statement: "When we write the K eq expression for a reaction with solids or liquids, we simply leave out the solids and the liquids". included in the K eq expression.
Calculate Keq, if the [N 2 O 4 ] is 0.00455 M & [NO 2] is 0.031M at equilibrium. Keq = [N 2 O 4] [NO 2]2 = [0.00455] [0.031]2 Keq = 4.73 Same Keq!!! Important! Keq is the same for a given reaction that is: at equilibrium at the same temperature no matter what the initial concentrations were.
Ka = [H+] [A-]/ [HA] pKa = - log Ka at half the equivalence point, pH = pKa = -log Ka
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